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fadeToggle() does not affect hidden() / visible()
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rndbit Offline
Member
Post: #1
fadeToggle() does not affect hidden() / visible()
As topic says... For some reason windows that are hidden using fadeToggle() still return visible()=true and hidden()=false.
06-10-2011 06:26 PM
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Esenthel Offline
Administrator
Post: #2
RE: [bug] fadeToggle() does not affect hidden() / visible()
did you check after the window finished fading out? (around 1 sec)
there's also Bool Window::hiding()
06-13-2011 07:47 PM
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